document.write( "Question 1201439: The number of tickets purchased by an individual for Beckham College’s holiday music festival is a uniformly distributed random variable ranging from 6 to 15.
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document.write( "Find the mean and standard deviation of this random variable. (Round your answers to 2 decimal places.) \n" );
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Algebra.Com's Answer #835812 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "Mean = 10.5 \n" ); document.write( "Standard Deviation = 2.87 (approximate)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The number of tickets is a discrete variable. \n" ); document.write( "It can only be equal to one of the following whole numbers {6,7,8,9,10,11,12,13,14,15} \n" ); document.write( "This random variable would be continuous if it made sense to have some fractional amount of tickets (eg: 6.785 tickets), but of course it doesn't make sense to have a fractional amount of tickets.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The mean of a discrete uniform random variable is found by adding up the endpoints, and then dividing in half. \n" ); document.write( "We are computing the midpoint. \n" ); document.write( "midpoint = (a+b)/2 \n" ); document.write( "midpoint = (6+15)/2 \n" ); document.write( "midpoint = 21/2 \n" ); document.write( "midpoint = 10.5 \n" ); document.write( "The mean is 10.5 \n" ); document.write( "It represents the center of the distribution. \n" ); document.write( "The proof should be fairly straight-forward, but let me know if you need me to go into more detail in this regard.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The standard deviation of a discrete uniform random variable isn't as straight-forward. \n" ); document.write( "The formula is \n" ); document.write( " \n" ); document.write( "One proof is found here \n" ); document.write( "https://proofwiki.org/wiki/Variance_of_Discrete_Uniform_Distribution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in a = 6 and b = 15 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "The standard deviation is approximately 2.87 \n" ); document.write( "The standard deviation is a measure how spread out a distribution is.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: \n" ); document.write( "Some textbooks will present the standard deviation formula as \n" ); document.write( " \n" ); document.write( "where n = b-a+1 represents the number of whole numbers from a to b, including both endpoints. \n" ); document.write( "Example: {6,7,8} has n = b-a+1 = 8-6+1 = 3 items. \n" ); document.write( " \n" ); document.write( " |