document.write( "Question 1201398: Jennifer, Grace, and Janet played Computer games. Jennifer won 30% of the total games, Grace 25%, and Janet 45%. There were no ties. What is the least possible number of the games that Jennifer won? \n" ); document.write( "
Algebra.Com's Answer #835759 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "The percentages add to 100%, so let's say 100 games total had been played.\r
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\n" ); document.write( "\n" ); document.write( "Each percentage corresponds to the whole number value shown here
  • Jennifer won 30 games
  • Grace won 25 games
  • Janet won 45 games
Simply erase the percent sign.\r
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\n" ); document.write( "\n" ); document.write( "Divide each value over 100 and reduce the fraction.
  • Jennifer: 30/100 = (10*3)/(10*10) = 3/10
  • Grace: 25/100 = (25*1)/(25*4) = 1/4
  • Janet: 45/100 = (5*9)/(5*20) = 9/20
The reduced fractions are
\n" ); document.write( "3/10, 1/4, 9/20\r
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\n" ); document.write( "\n" ); document.write( "The LCD is 20, so let's rewrite each denominator in terms of the LCD
  • Jennifer: 3/10 = (3*2)/(10*2) = 6/20
  • Grace: 1/4 = (1*5)/(4*5) = 5/20
  • Janet: 9/20 = 9/20
If 20 games were played, then,
  • Jennifer won 6/20 of those games. She won 6 games.
  • Grace won 5/20 of those games. She won 5 games.
  • Janet won 9/20 of those games. She won 9 games.
This scenario represents the fewest number of games played.
\n" ); document.write( "This is because the nature of the LCD is to go for the lowest denominator, i.e. lowest number of games in this case.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 6\r
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\n" ); document.write( "\n" ); document.write( "This method is probably a bit more convoluted, so it might be more effective to use another route.
\n" ); document.write( "But it's always a good idea to have multiple pathways.
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