document.write( "Question 1201400: Two cards are drawn from a standard deck of cards. Find each probability\r
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document.write( "P(both kings or both black cards) \r
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document.write( "P(both face cards or both red) \n" );
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Algebra.Com's Answer #835749 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Problem 1 \n" ); document.write( "P(both kings or both black cards) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 4 kings \n" ); document.write( "There are 52 cards total \n" ); document.write( "4/52 = 1/13 = probability of getting a king \n" ); document.write( "Assuming the card is not put back (aka no replacement), then \n" ); document.write( "4-1 = 3 kings left \n" ); document.write( "52-1 = 51 cards left \n" ); document.write( "3/51 = 1/17 = probability of getting another king, no replacement \n" ); document.write( "P(2 kings) = P(1st king)*P(2nd king) \n" ); document.write( "P(2 kings) = (4/52)*(3/51) \n" ); document.write( "P(2 kings) = (1/13)*(1/17) \n" ); document.write( "P(2 kings) = 1/221\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "26 black cards (13 spades + 13 clubs) \n" ); document.write( "52 cards total \n" ); document.write( "26/52 = 1/2 = probability of getting a black card \n" ); document.write( "26-1 = 25 black cards left \n" ); document.write( "52-1 = 51 cards left \n" ); document.write( "25/51 = probability of getting another black card, no replacement \n" ); document.write( "P(2 black cards) = P(1st black card)*P(2nd black card) \n" ); document.write( "P(2 black cards) = (26/52)*(25/51) \n" ); document.write( "P(2 black cards) = (1/2)*(25/51) \n" ); document.write( "P(2 black cards) = 25/102\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 black kings \n" ); document.write( "52 cards total \n" ); document.write( "P(2 black kings) = P(1st black king)*P(2nd black king) \n" ); document.write( "P(2 black kings) = (2/52)*(1/51) \n" ); document.write( "P(2 black kings) = 1/1326\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(2 kings or 2 black) = P(2 kings) + P(2 black) - P(2 black kings) \n" ); document.write( "P(2 kings or 2 black) = 1/221 + 25/102 - 1/1326 \n" ); document.write( "P(2 kings or 2 black) = 6/1326 + 325/1326 - 1/1326 \n" ); document.write( "P(2 kings or 2 black) = (6 + 325 - 1)/1326 \n" ); document.write( "P(2 kings or 2 black) = 330/1326 \n" ); document.write( "P(2 kings or 2 black) = (6*55)/(6*221) \n" ); document.write( "P(2 kings or 2 black) = 55/221\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=====================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Problem 2 \n" ); document.write( "P(both face cards or both red)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "face cards = Jack, Queen, King \n" ); document.write( "3 face cards in any given suit \n" ); document.write( "4*3 = 12 face cards in the deck\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(2 face cards) = P(1st face card)P*(2nd face card) \n" ); document.write( "P(2 face cards) = (12/52)*(11/51) \n" ); document.write( "P(2 face cards) = (3/13)*(11/51) \n" ); document.write( "P(2 face cards) = 11/221 \n" ); document.write( "I'm assuming that we are not replacing the 1st card.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "26 red cards (13 hearts + 13 diamonds) \n" ); document.write( "P(2 red cards) = P(1st red card)*P(2nd red card) \n" ); document.write( "P(2 red cards) = (26/52)*(25/51) \n" ); document.write( "P(2 red cards) = (1/2)*(25/51) \n" ); document.write( "P(2 red cards) = 25/102\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6 cards are red and a face card (eg: King of Diamonds) \n" ); document.write( "P(2 red face cards) = P(1st red face)*P(2nd red face) \n" ); document.write( "P(2 red face cards) = (6/52)*(5/51) \n" ); document.write( "P(2 red face cards) = (3/26)*(5/51) \n" ); document.write( "P(2 red face cards) = 15/1326 \n" ); document.write( "P(2 red face cards) = 5/442\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(2 face or 2 red) = P(2 face) + P(2 red) - P(2 red face) \n" ); document.write( "P(2 face or 2 red) = 11/221 + 25/102 - 5/442 \n" ); document.write( "P(2 face or 2 red) = 66/1326 + 325/1326 - 15/1326 \n" ); document.write( "P(2 face or 2 red) = (66 + 325 - 15)/1326 \n" ); document.write( "P(2 face or 2 red) = 376/1326 \n" ); document.write( "P(2 face or 2 red) = (2*188)/(2*663) \n" ); document.write( "P(2 face or 2 red) = 188/663\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=====================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summary\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(both kings or both black cards) = 55/221 \n" ); document.write( "P(both face cards or both red) = 188/663\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 1st card wasn't put back, aka no replacement. \n" ); 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