document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114906>Question 114906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "2x-y=3<BR>\n" );
document.write( "x-2y=-6\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83574 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X-2Y=-6 OR X=2Y-6 NOW SUBSTITUTE (2Y-6) FOR X IN THE OTHER EQUATRION & SOLVE FOR Y:<BR>\n" );
document.write( "2(2Y-6)-Y=3<BR>\n" );
document.write( "4Y-12-Y=3<BR>\n" );
document.write( "3Y=3+12<BR>\n" );
document.write( "3Y=15<BR>\n" );
document.write( "Y=15/3<BR>\n" );
document.write( "Y=5 ANSWER.<BR>\n" );
document.write( "X-2*5=-6<BR>\n" );
document.write( "X-10=-6<BR>\n" );
document.write( "X=-6+10<BR>\n" );
document.write( "X=4 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*4-5=3<BR>\n" );
document.write( "8-5=3<BR>\n" );
document.write( "3=3<BR>\n" );
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