document.write( "Question 1201392: the ratio of pickups to cars sold at a dealership is 2 to 3. If the dealership sold 142 more cars than pickups in 1999, then how many of each did it sell \n" ); document.write( "
Algebra.Com's Answer #835726 by Theo(13342)\"\" \"About 
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let x = number of pickups.
\n" ); document.write( "let y = number of cars.
\n" ); document.write( "you get:
\n" ); document.write( "x/y = 2/3.
\n" ); document.write( "the dealership sold 142 more cars than pickups.
\n" ); document.write( "you get y = x + 142
\n" ); document.write( "in the equation of x/y = 2/3, replace y with x + 142 to get:
\n" ); document.write( "x/(x+142) = 2/3
\n" ); document.write( "cross multiply to get:
\n" ); document.write( "3x = 2*(x+142)
\n" ); document.write( "simplify to get:
\n" ); document.write( "3x = 2x + 284
\n" ); document.write( "subtract 2x from both sides of the equation to get:
\n" ); document.write( "x = 284.
\n" ); document.write( "this tells you that the number of pickups is 284.
\n" ); document.write( "the number of cars is 142 more than that = 426.
\n" ); document.write( "x/y becomes equal to 284/426.
\n" ); document.write( "simplify that fraction to get:
\n" ); document.write( "x/y = 2/3, confirming the values of x and y are correct.\r
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