document.write( "Question 1201312: if the mean is 266 and standard deviation is 12 and the question is asking what percentage last more than 283: p(x>283). how do i do this \n" ); document.write( "

Algebra.Com's Answer #835621 by math_helper(2461) $\"\"$ $\"About$

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document.write( "Calculate the z-score:  (283-266)/12 = 1.41667\r
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document.write( "Now find a positive z-table and go down to row \"1.4\" and across to column \"0.02\"  (rounded 1.41667 to 1.42).  You will see  0.92220.\r
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document.write( "This number is the fraction less than 283.  You stated you want P(x>283) so you take 1-0.92220 to get 0.0778.  
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document.write( "Converting this to a percentage,  7.78% of the samples will be greater than 283. \n" );
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