document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201293>Question 1201293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When solving an equation with variables in denominators, we must determine the values that cause these denominators to equal 0, so that we can reject these values if they appear as proposed solutions. Find all values for which at least one denominator is equal to 0. Write answers using the symbol Do not solve.\r<BR>\n" );
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document.write( "\frac{-1}{\left(x+3\right)\left(x-4\right)}=\frac{1}{2\left(x+1\right)} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835592 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \frac{-1}{\left(x+3\right)\left(x-4\right)}=\frac{1}{2\left(x+1\right)}<BR>\n" );
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document.write( "Gibberish. </SPAN>\n" );
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