document.write( "Question 114865This question is from textbook Harcourt Math
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document.write( ": A group of goats and ducks have a total of 99 heads and legs among them. There are twice as many ducks as there are goats. How many are there of each? \n" );
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Algebra.Com's Answer #83550 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! g = number of goats \n" ); document.write( "d = number of ducks\r \n" ); document.write( "\n" ); document.write( "Each goat has 1 head and 4 legs, so there are 5g heads and legs supplied by the goats. \n" ); document.write( "Each duck has 1 head and 2 legs, so there are 3d heads and legs supplied by the ducks\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We also know that there are twice as many ducks as goats, so \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "9 goat heads \n" ); document.write( "4 * 9 = 36 goat legs \n" ); document.write( "18 duck heads \n" ); document.write( "2 * 18 = 36 duck legs\r \n" ); document.write( "\n" ); document.write( "9 + 36 + 18 + 36 = 99, Check! \n" ); document.write( " |