document.write( "Question 1201169: 3. 8. 1 Trigonometric Identities and Application Help me quickly as possible\r
\n" ); document.write( "\n" ); document.write( "A student solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. What was the student's error?\r
\n" ); document.write( "\n" ); document.write( "Please give the correct answer. Describe the student's error with a full explanation and show your work. Please answer me as quickly as possible. \n" ); document.write( "
Algebra.Com's Answer #835432 by Theo(13342)\"\" \"About 
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sin2x / cosx = 2
\n" ); document.write( "multiply both sides of the equation by cosx to get:
\n" ); document.write( "sin2x = 2cosx
\n" ); document.write( "sin2x = 2sinxcosx, therefore:
\n" ); document.write( "2sinxcosx = 2cosx
\n" ); document.write( "divide both sidee of the equation by 2cosx to get:
\n" ); document.write( "sinx = 1
\n" ); document.write( "this occures when x = 90 degrees or 270 degrees.
\n" ); document.write( "90 degrees * pi/180 = pi/2
\n" ); document.write( "270 degrees * pi/180 = 3pi/2
\n" ); document.write( "therefore, this occurs when x = 90 or 270 degrees, and it occurs when x = pi/2 or 3pi/2.
\n" ); document.write( "here's a graph that shows when y = sin(2x) and when y = 2cos(x).
\n" ); document.write( "the interesection is when sin(2x) = 2cos(x)
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