document.write( "Question 1201160: Jessie is three years older than Miguel. Twenty years from now, the sum of their ages is 51. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #835419 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Let Miguel's present age be x
\n" ); document.write( "Jessie's age now will be x+3\r
\n" ); document.write( "\n" ); document.write( "After 20 years
\n" ); document.write( "Miguel's age will be x+20
\n" ); document.write( "Jessie'sage will be x+3 +20\r
\n" ); document.write( "\n" ); document.write( "x+20 +x+3 +20 =51
\n" ); document.write( "2x +43=51
\n" ); document.write( "2x =51-43
\n" ); document.write( "2x =8
\n" ); document.write( "x =8/2
\n" ); document.write( "x=4 Miguel's age
\n" ); document.write( "Jessie's age 4+3 =7 years\r
\n" ); document.write( "\n" ); document.write( "x
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