document.write( "Question 1201150: A certain automobile cooling system contains 12.0 L of coolant that is 15% antifreeze.\r
\n" ); document.write( "\n" ); document.write( "How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 23% antifreeze will result?
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Algebra.Com's Answer #835412 by mananth(16946)\"\" \"About 
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\n" ); document.write( "A certain automobile cooling system contains 12.0 L of coolant that is 15% antifreeze.\r
\n" ); document.write( "\n" ); document.write( "How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 23% antifreeze will result?\r
\n" ); document.write( "\n" ); document.write( "Initialquantity = 12L
\n" ); document.write( "strength = 15%\r
\n" ); document.write( "\n" ); document.write( "remove x litres
\n" ); document.write( "Solution remaining = (12-x)
\n" ); document.write( "You add pure antifreeze to replace x
\n" ); document.write( "Final antifreeze 23% 12 L\r
\n" ); document.write( "\n" ); document.write( "(12-x)*15% +100%*x = 23%*12
\n" ); document.write( "Multiply by 100 the equation
\n" ); document.write( "(12-x)*15 +100x=23*12
\n" ); document.write( "180-15x+100x=276
\n" ); document.write( "85x =96
\n" ); document.write( "x =96/85
\n" ); document.write( "=1.13 L has to be removed\r
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