document.write( "Question 1201150: A certain automobile cooling system contains 12.0 L of coolant that is 15% antifreeze.\r
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document.write( "How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 23% antifreeze will result? \n" );
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Algebra.Com's Answer #835412 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A certain automobile cooling system contains 12.0 L of coolant that is 15% antifreeze.\r \n" ); document.write( "\n" ); document.write( "How many liters of mixture must be removed so that, when it is replaced with pure antifreeze, a mixture of 23% antifreeze will result?\r \n" ); document.write( "\n" ); document.write( "Initialquantity = 12L \n" ); document.write( "strength = 15%\r \n" ); document.write( "\n" ); document.write( "remove x litres \n" ); document.write( "Solution remaining = (12-x) \n" ); document.write( "You add pure antifreeze to replace x \n" ); document.write( "Final antifreeze 23% 12 L\r \n" ); document.write( "\n" ); document.write( "(12-x)*15% +100%*x = 23%*12 \n" ); document.write( "Multiply by 100 the equation \n" ); document.write( "(12-x)*15 +100x=23*12 \n" ); document.write( "180-15x+100x=276 \n" ); document.write( "85x =96 \n" ); document.write( "x =96/85 \n" ); document.write( "=1.13 L has to be removed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |