document.write( "Question 1201141: In regular pentagon ABCDE, draw diagonal AC. Prove that segments AC and DE are parallel. \n" ); document.write( "
Algebra.Com's Answer #835405 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "All sides of pentagon equal
\n" ); document.write( "Interior angles of polygon =108 deg\r
\n" ); document.write( "\n" ); document.write( "AB=BC in triangle ABC Isoscles triangle
\n" ); document.write( "AE =ED in triangle AED Isoscles triangle\r
\n" ); document.write( "\n" ); document.write( "Sum of anglesof triangle =180 deg\r
\n" ); document.write( "\n" ); document.write( "36+36+108=180 deg\r
\n" ); document.write( "\n" ); document.write( "Angle BAE = 108
\n" ); document.write( "Therefore angle CAD =36 deg\r
\n" ); document.write( "\n" ); document.write( "Angle BAD = angle ADE\r
\n" ); document.write( "\n" ); document.write( "But they are alternate angles forme by transversal AD
\n" ); document.write( "Therefore AC || DE\r
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