document.write( "Question 114797This question is from textbook
\n" ); document.write( ": Hi, I'm having trouble with this particular math problem and it would be very helpful if you can help me. The problem is: John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mi/h and travels 35 mi farther than Mary, who drives at 40 mi/h. Mary's tyip takes 15 min longer than John's. For what length of time does each of them drive? \n" ); document.write( "
Algebra.Com's Answer #83538 by ankor@dixie-net.com(22740)\"\" \"About 
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John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mi/h and travels 35 mi farther than Mary, who drives at 40 mi/h. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?
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\n" ); document.write( "Let t = John's driving time
\n" ); document.write( "then
\n" ); document.write( "(t+.25) = Mary's driving time (changed 15 min to .25 hr)
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\n" ); document.write( "Write a distance equation Distance = speed * time:
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\n" ); document.write( "J's distance - 35 = M's distance
\n" ); document.write( "60t - 35 = 40(t+.25)
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\n" ); document.write( "60t - 35 = 40t + 10
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\n" ); document.write( "60t - 40t = 10 + 35
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\n" ); document.write( "20t = 45
\n" ); document.write( ":
\n" ); document.write( "t = 45/20
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\n" ); document.write( "t = 2.25 hrs is John's driving time
\n" ); document.write( "and
\n" ); document.write( "2.25 + .25 = 2.5 hrs is Mary's driving time
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\n" ); document.write( "Check solutions by finding the distance each drives:
\n" ); document.write( "J: 2.25 *60 = 135 mi
\n" ); document.write( "M: 2.50 *40 = 100 mi
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\n" ); document.write( "difference = 35 mi
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