document.write( "Question 1201107: A surveyor standing W 25 degrees S of a tower measures the angle of elevation of the top of the tower as 40 degrees 30. From a position E 23 degrees S from the tower the l elevation of the top is 37 degrees 15. Determine the height of the tower if the distance between the two observations is 75m. \n" ); document.write( "
Algebra.Com's Answer #835362 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Notation like 40°30' is read out as \"40 degrees 30 minutes\". \n" ); document.write( "\"minutes\" refers specifically to arc minutes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 60 arc minutes in a full degree. \n" ); document.write( "30 arc minutes is 30/60 = 1/2 = 0.5 of a degree. \n" ); document.write( "15 arc minutes is 15/60 = 1/4 = 0.25 of a degree.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( "40 degrees 30 minutes = 40.5 degrees \n" ); document.write( "37 degrees 15 minutes = 37.15 degrees \n" ); document.write( "which represent the angles of elevation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is what it looks like from a birds eye view \n" ); document.write( " \n" ); document.write( "A = location of the surveyor \n" ); document.write( "B = second observation location \n" ); document.write( "C = location of the tower \n" ); document.write( "Notation like W 25° S means \"aim directly west, then turn 25° toward the south\" \n" ); document.write( "The blue dashed line in the diagram above helps us set up the angles of 25° and 23°\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Refer to this page for a few other examples \n" ); document.write( "http://academic.brooklyn.cuny.edu/geology/leveson/core/linksa/comp.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, refer to this problem involving similar compass bearings notation. \n" ); document.write( "https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1200155.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle ACB is sandwiched between the 25 and 23 degree angles. \n" ); document.write( "Those three angles add to 180. \n" ); document.write( "25+(angleACB)+23 = 180 \n" ); document.write( "angleACB + 48 = 180 \n" ); document.write( "angle ACB = 180-48 \n" ); document.write( "angle ACB = 132\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's update the drawing with that angle. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's a 3D look at what's going on. \n" ); document.write( "Pay close attention to the points A,B,C how they are laid out. \n" ); document.write( "Compare their relative locations to the previous diagram shown above. \n" ); document.write( " \n" ); document.write( "triangle ABC is along the flat ground \n" ); document.write( "A = location of the surveyor \n" ); document.write( "B = second observation location \n" ); document.write( "C = base of the tower \n" ); document.write( "D = top of the tower \n" ); document.write( "x = height of the tower = length of segment CD \n" ); document.write( "angle ACB = 132 degrees \n" ); document.write( "angle CAD = 40.5 degrees \n" ); document.write( "angle CBD = 37.25 degrees\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is the side view of right triangle ACD \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is the side view of right triangle BCD \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At this point I get stuck. \n" ); document.write( "I don't think there's enough information to determine x. \n" ); document.write( "If we knew the length of segment AC or the length of segment BC, then we could use trigonometry to determine x. \n" ); document.write( " \n" ); document.write( " |