document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201108>Question 1201108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Adom is now five times as old as Asempa. In ten years time Adom will three <BR>\n" );
document.write( "times as old as kweme. How old are they? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835352 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Asempa be x years<BR>\n" );
document.write( "Adom will be 5x years\r<BR>\n" );
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document.write( "After 10 years\r<BR>\n" );
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document.write( "Asempa will be x+10 years<BR>\n" );
document.write( "Adom will bw (5x+10) years\r<BR>\n" );
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document.write( "adom s age = 3 times Asempa s age\r<BR>\n" );
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document.write( "5x+10 = 3(x+10)\r<BR>\n" );
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document.write( "5x+10 = 3x+30<BR>\n" );
document.write( "5x-3x=30-10<BR>\n" );
document.write( "2x =20<BR>\n" );
document.write( "x=10 Asempa s age<BR>\n" );
document.write( "Adom s age = 10*5 = 50 years\r<BR>\n" );
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document.write( " </SPAN>\n" );
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