document.write( "Question 1201106: A vertical aerial AB 9.6m high stands on ground which is inclined 12 degrees to the horizontal. A stay connects the top of the aerial A to a point C on the ground 10m downhill from B the foot of the aerial. Determine the length of the stay and the angle the stay makes with the ground. \n" ); document.write( "
Algebra.Com's Answer #835351 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AB =9.6 m\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "90-12 = 78\r \n" ); document.write( "\n" ); document.write( "Law of cosines\r \n" ); document.write( "\n" ); document.write( "AC^2 =AB^2+BC^2 −2(AB)(BC)cos∠ABC \n" ); document.write( " = (9.6)^2 + (10)^2 - 2*(10)*(9.6)*cos (78deg) \n" ); document.write( "=152.24 m \n" ); document.write( "length of the stay = 152.24 m\r \n" ); document.write( "\n" ); document.write( "Law of sines \n" ); document.write( "(sin∠ACB/AB ) = (sin∠ABC/AC)\r \n" ); document.write( "\n" ); document.write( "Find the angle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |