document.write( "Question 1201106: A vertical aerial AB 9.6m high stands on ground which is inclined 12 degrees to the horizontal. A stay connects the top of the aerial A to a point C on the ground 10m downhill from B the foot of the aerial. Determine the length of the stay and the angle the stay makes with the ground. \n" ); document.write( "
Algebra.Com's Answer #835351 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "AB =9.6 m\r
\n" ); document.write( "\n" ); document.write( "\"%28alpha%29\" = 12 deg. \"%28beta%29+=+%2890-%28alpha%29%29\"\r
\n" ); document.write( "\n" ); document.write( "90-12 = 78\r
\n" ); document.write( "\n" ); document.write( "Law of cosines\r
\n" ); document.write( "\n" ); document.write( "AC^2 =AB^2+BC^2 −2(AB)(BC)cos∠ABC
\n" ); document.write( " = (9.6)^2 + (10)^2 - 2*(10)*(9.6)*cos (78deg)
\n" ); document.write( "=152.24 m
\n" ); document.write( "length of the stay = 152.24 m\r
\n" ); document.write( "\n" ); document.write( "Law of sines
\n" ); document.write( "(sin∠ACB/AB ) = (sin∠ABC/AC)\r
\n" ); document.write( "\n" ); document.write( "Find the angle\r
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