document.write( "Question 1201075: Hello I'm having trouble with this one, thanks for the help. The dimensions of a picture inside a frame of uniform width are 12 by 16
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Algebra.Com's Answer #835324 by josgarithmetic(39617)\"\" \"About 
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\n" ); document.write( " The dimensions of a picture inside a frame of uniform width are 12 by 16
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\n" ); document.write( "\n" ); document.write( "Taking away the modifier in the first part,
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\n" ); document.write( " The dimensions of a picture -modifier- are 12 by 16
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\n" ); document.write( "\n" ); document.write( "Then the area of the picture alone, is \"12%2A16=192\" square inches.\r
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\n" ); document.write( "\n" ); document.write( "Make the drawing and label parts. If u is the uniform width of the frame, then the area of frame PLUS pucture is \"%2812%2B2u%29%2816%2B2u%29\".\r
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\n" ); document.write( "\n" ); document.write( "Second part of description,
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\n" ); document.write( "whole area (picture and frame) is 288 square inches
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\n" ); document.write( "\n" ); document.write( "You already know from description that the frame surrounds the picture, and is of a uniform width. Using the given total area,
\n" ); document.write( "\"highlight_green%28%2812%2B2u%29%2816%2B2u%29=288%29\"
\n" ); document.write( "And you can solve this equation with whatever skills you have or need. (You might want to first multiply both sides of equation by \"1%2F4\").
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