document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201050>Question 1201050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that, for a certain exam, a teacher grades on a curve.\r<BR>\n" );
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document.write( "It is known that the mean is 65 and the standard deviation is 10. There are 45 students in the class.\r<BR>\n" );
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document.write( "What score would be necessary to obtain an A?<BR>\n" );
document.write( "99<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835305 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the mean is 65<BR>\n" );
document.write( "the standard deviation is 10<BR>\n" );
document.write( "the class size is 45.<BR>\n" );
document.write( "you would need to know what percent of the class fall into each category.<BR>\n" );
document.write( "assuming the distribution is normal, and assuming that 2% of the class are assumed to get an A, then you would look for what score is required to be in the top 2% of the class, grade wise.<BR>\n" );
document.write( "using the normal distribution calculator at <a  rel=nofollow HREF= \"https://davidmlane.com/hyperstat/z_table.html\" target = \"_blank\">https://davidmlane.com/hyperstat/z_table.html</a>, it looks like the grade that would be required to get an A in this class would be a score greater than 85.<BR>\n" );
document.write( "here are the results from using that calculator.\r<BR>\n" );
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