document.write( "Question 1201030: In a survey of 1000 adults aged 18 and older, the following question was posed:
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document.write( "\"Are other travelers' online reviews trustworthy?\" The participants were asked
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document.write( "to answer \"yes,\" \"no,\" or \"not sure.\" The survey revealed that 340 answered \"no\"
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document.write( "or \"not sure.\" It also showed that the number of those who answered \"yes\"
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document.write( "exceeded the number of those who answered \"no\" by 400. What percentage of
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document.write( "respondents answered \"yes,\" \"no,\" and \"not sure\"? (Let x represent the number of
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document.write( "respondents who answered \"yes\", y represent the number of respondents who
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document.write( "answered \"no\", and z represent the number of respondents who answered \"not
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document.write( "sure\".)
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document.write( " ? = 1000
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document.write( " ? = 340
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document.write( " ? = 400\r
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Algebra.Com's Answer #835297 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! ...1000 adults... (yes's) + (no's) + (not sure's) = 1000\r\n" ); document.write( " x + y + z = 1000...340 answered \"no\" or \"not sure.\"... (no's) + (not sure's) = 340\r\n" ); document.write( " y + z = 340...the number of those who answered \"yes\" \n" ); document.write( "exceeded the number of those who answered \n" ); document.write( "\"no\" by 400... (yes's) - (no's) = 400\r\n" ); document.write( " x - y = 400\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |