document.write( "Question 1201038: No length of a lumber, a machine cuts are normally distributed by a mean of 89 inches and a standard deviation of 0.5 inch part a what is the probability that a randomly selected board cut by the machine has a length greater than 89.12 inches part B hey sample of 41 boards is randomly selected what is the probability that their main length is greater than 89.12 inches \n" ); document.write( "
Algebra.Com's Answer #835290 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the lengths of lumber a machine cuts are normally distributed with a mean of 89 inches and a standard deviation of 0.5 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "part a: \n" ); document.write( "what is the probability that a randomly selected board cut by the machine has a length greater than 89.12 inches.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "part b: \n" ); document.write( "what is the probability that a randomly selected sample of 41 boardshas a mean length greater than 89.12 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "answer to part a: \n" ); document.write( "mean is 89 inches. \n" ); document.write( "standard deviation is .5 inches. \n" ); document.write( "probability that the board has a length greater than 89.12 inches is .4052.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "answer to part b: \n" ); document.write( "mean is 89 inches \n" ); document.write( "standard deviation is .5 \n" ); document.write( "sample size is 41 \n" ); document.write( "standard error is .5 / sqrt(41) = .0780868809. \n" ); document.write( "probability that the mean length of the sample will be greater thana 89.12 is .06217731.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when you are dealing with a sample of one element, use the standard deviation. \n" ); document.write( "when you are dealing with the mean of a sample of more than 1 element, use the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the standard error is equal to the standard deviation divided by the square root of the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's what the results look like on the calculator at https://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "display from patt a:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "display from part b:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |