document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201033>Question 1201033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car and a bust left regina at the same time. the car drove 480km west to calgary. the bus drove 570 km east to winnipeg. the bus travelled 15 km/hr faster than the car. they arrived at the destinations at the same time. what was the speed of the car ? what was the speed of the bus ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835281 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor showed one formal algebraic method for solving the problem.<br><BR>\n" );
document.write( "If formal algebra is not required, here is a quick and easy informal solution.<br><BR>\n" );
document.write( "The times for the two vehicles are the same; so the difference in distances is equal to the difference in speeds, multiplied by that amount of time.<br><BR>\n" );
document.write( "The difference in distances was 570-480 = 90 km; the difference in speeds was 15 km/hr.  That means the time for both vehicles was 90/15 = 6 hours.<br><BR>\n" );
document.write( "So the speed of the car was 480/6 = 80 km/hr and the speed of the bus was 570/6 = 95 km/hr.<br><BR>\n" );
document.write( "ANSWERS:<BR>\n" );
document.write( "car 80 km/hr<BR>\n" );
document.write( "bus 95 km/hr<br><BR>\n" );
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