document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201029>Question 1201029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	The owner of the Rancho Los Feliz has 9000 yd of fencing with which to enclose a rectangular piece of grazing land along the straight portion of a river. Fencing is not required along the river, and the length of the fencing parallel to the river is to exceed the length of the fencing perpendicular to it by 4500 yd. Find the area of the enclosed land (in sq yd). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835273 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = lengh<BR>\n" );
document.write( "b = width<BR>\n" );
document.write( "a + 2b = 9000<BR>\n" );
document.write( "a = b + 4500<BR>\n" );
document.write( "replace a with b + 4500 to get:<BR>\n" );
document.write( "b + 4500 + 2b = 9000<BR>\n" );
document.write( "combine like terms and subtract 4500 from both sides of the equation to get:<BR>\n" );
document.write( "3b = 4500<BR>\n" );
document.write( "solve for b to get b = 1500<BR>\n" );
document.write( "since a = b + 4500, then a = 6000<BR>\n" );
document.write( "a + 2b becomes 6000 + 3000 = 9000<BR>\n" );
document.write( "a is the length = 6000<BR>\n" );
document.write( "b is the width = 1500<BR>\n" );
document.write( "the area of the enclosed space is a * b = 6000 * 1500 = 9,000,000 square yards.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );