document.write( "Question 1201011: on a trip jennifer noticed that her car averaged 21 mi/gal of gas except for the days she used the air conditioning, and then it averaged only 17 mi/gal. if she use 91 gal of gas to drive 1751 mi, on how many of those miles did she used the air conditioning?\r
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Algebra.Com's Answer #835238 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "on a trip jennifer noticed that her car averaged 21 mi/gal of gas except
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document.write( "Let x be the miles where she used the air conditioning.\r\n" );
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document.write( "Then miles where she didn't use the air conditioning were (1751-x).\r\n" );
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document.write( "Now we can write this equation for the total gas spent\r\n" );
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document.write( "    \"x%2F21\" + \"%281751-x%29%2F17\" = 91 gallons of gas (total).    (*)\r\n" );
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document.write( "    +------------------------------------------------+\r\n" );
document.write( "    |    At this point, the setup is just complete,  |\r\n" );
document.write( "    |    and our task is to solve this equation.     |\r\n" );
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document.write( "For it, multiply both sides by 21*17.  You will get\r\n" );
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document.write( "    17x + 21*(1751-x) = 91*21*17\r\n" );
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document.write( "    17x + 21*1751 - 21x = 32487\r\n" );
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document.write( "    17x - 21x = 32487 - 21*1751\r\n" );
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document.write( "       -4x    =    -4284\r\n" );
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document.write( "         x    =    \"%28-4284%29%2F%28-4%29\" = 1071.\r\n" );
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document.write( "ANSWER.  She used the air conditioning on 1071 miles.\r\n" );
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document.write( "CHECK.  I will check if equation (*) is held.\r\n" );
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document.write( "        \"1071%2F21\" + \"%281751-1071%29%2F17\" = 51 + 40 = 91 gallon of gas, in total.   ! Correct !\r\n" );
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