document.write( "Question 1200959: show that if A-B-C and B-C-D,then A-B-D and A-C-D \n" ); document.write( "
Algebra.Com's Answer #835220 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Now let's get this straight.  Your problem is:
show that if A-B-C and B-C-D,then A-B-D and A-C-D
That doesn't make any sense, as I told you before.\r\n" );
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document.write( "Suppose A=7, B=3, C=2, D=1.\r\n" );
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document.write( "A-B-C = 7-3-2 = 2  \r\n" );
document.write( "B-C-D = 3-2-1 = 0\r\n" );
document.write( "A-B-D = 7-3-1 = 3\r\n" );
document.write( "A-C-D = 7-2-1 = 4\r\n" );
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document.write( "Let's substitute those values in what you wrote, which was:
show that if A-B-C and B-C-D,then A-B-D and A-C-D
We get:
show that if 2 and 0,then 3 and 4
Do you think that makes any sense?  If so, you are the only\r\n" );
document.write( "person on the planet who thinks it does.\r\n" );
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document.write( "Edwin
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