document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114792>Question 114792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man lived a fourth of his life as a boy, a fifth as a young man and a third as an adult. He spent 13 years in his old age. How old was he when he died? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83522 by </B><A HREF=/tutors/aboutme.mpl?userid=ganesh><B>ganesh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganesh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the age when the man died.\r<BR>\n" );
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document.write( "Then (1/4)x + (1/5)x + (1/3)x + 13 = x  ( Since, a fourth of his life was lived as a boy can be written as (1/4)x.\r<BR>\n" );
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document.write( "Solve the above equation. \r<BR>\n" );
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document.write( "(1/4)x + (1/5)x + (1/3)x - x = -13\r<BR>\n" );
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document.write( "(1/60){15x +12x + 20x - 60x}= -13   ( Take LCM)<BR>\n" );
document.write( "-13x = -780<BR>\n" );
document.write( "x = 60.\r<BR>\n" );
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document.write( "The age of death is 60 </SPAN>\n" );
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