document.write( "Question 1200974: divide N102 among three boys A, B and C , so that A gets twice as much as B and C gets 1 1/2 times as much as A. How much does each boy get?
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Algebra.Com's Answer #835195 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The algebra for solving a problem like this is almost always easier if you take the time to analyze the given information so that you can set up the problem using a single variable.

\n" ); document.write( "The number given to B is the smallest, so

\n" ); document.write( "let x = number given to B
\n" ); document.write( "then 2x = number given to A (twice as many as B)
\n" ); document.write( "and 3x = number given to C (1 1/2 times as many as A)

\n" ); document.write( "The total is 102:

\n" ); document.write( "\"x%2B2x%2B3x=102\"
\n" ); document.write( "\"6x=102\"
\n" ); document.write( "\"x=102%2F6=17\"

\n" ); document.write( "ANSWERS:
\n" ); document.write( "A: 2x = 34
\n" ); document.write( "B: x = 17
\n" ); document.write( "C: 3x = 51

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