document.write( "Question 1200974: divide N102 among three boys A, B and C , so that A gets twice as much as B and C gets 1 1/2 times as much as A. How much does each boy get?
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Algebra.Com's Answer #835192 by Theo(13342)\"\" \"About 
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A gets twice as much as B.
\n" ); document.write( "C gets 1 and 1/2 times as much as A.
\n" ); document.write( "let a = the amount that A gets.
\n" ); document.write( "let b = the amount that B gets.
\n" ); document.write( "let c = the amount that C gets.
\n" ); document.write( "your equations are:
\n" ); document.write( "a = 2 * b.
\n" ); document.write( "c = 3/2 * a.
\n" ); document.write( "since a = 2 * b, then c = 3/2 * 2 * b = 3 * b.
\n" ); document.write( "you get:
\n" ); document.write( "a = 2 * b
\n" ); document.write( "b = b
\n" ); document.write( "c = 3 * b
\n" ); document.write( "a + b + c = 102 becomes 2 * b + b + 3 * b = 102
\n" ); document.write( "combine like terms to get 6 * b = 102
\n" ); document.write( "solve for b to bet:
\n" ); document.write( "b = 102/6 = 17
\n" ); document.write( "solve for a to get a = 2 * b = 34
\n" ); document.write( "solve for c to get c = 3 * b = 51.
\n" ); document.write( "a + b + c = 34 + 17 + 51 = 102, confirming the values for a,b,c are correct.\r
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\n" ); document.write( "\n" ); document.write( "another way to solve is to translate everything to a, rather than b.
\n" ); document.write( "start with:
\n" ); document.write( "a = 2b
\n" ); document.write( "c = 3/2 * a
\n" ); document.write( "from a = 2b, solve for b to get b = a/2.
\n" ); document.write( "a is now equal to a.
\n" ); document.write( "b is equal to a/2.
\n" ); document.write( "c is equal to 3/2 * a.
\n" ); document.write( "a + b + c = 102 becomes a + a/2 + 3/2 * a = 102.
\n" ); document.write( "combine like terms to get 6a/2 = 102
\n" ); document.write( "multiply both sides of this equation by 2 to get:
\n" ); document.write( "6a = 204.
\n" ); document.write( "solve for a to get:
\n" ); document.write( "a = 34.
\n" ); document.write( "since b = a/2, then b = 17
\n" ); document.write( "since c = 3/2 * a, then c = 51.\r
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\n" ); document.write( "\n" ); document.write( "you get the same values for a,b,c either way.\r
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\n" ); document.write( "\n" ); document.write( "your solution is:
\n" ); document.write( "A gets N34
\n" ); document.write( "B gets N17
\n" ); document.write( "C gets N51\r
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