document.write( "Question 1200968: Amy, Betty and Casey decided to buy a camera for their father. Amy would pay 30% of the usual price of the camera. Betty would pay 2/5 of the remaining amount and Casey will pay the rest. At the shop, the price of the camera had increased by 25% of its usual price. As a result, Amy paid $255 for the camera.
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\n" ); document.write( "(b) How much did Casey have to pay in the end?
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Algebra.Com's Answer #835189 by josgarithmetic(39620)\"\" \"About 
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p, usual price for the camera
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document.write( "                 HOW MUCH EACH PAID\r\n" );
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document.write( "AMY             (0.3)p\r\n" );
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document.write( "BETTY           (2/5)(1.25p-0.3p)\r\n" );
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document.write( "CASEY          1.25p-(0.3)p-(2/5)(1.25p-0.3p)\r\n" );
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document.write( "Total           1.25p\r\n" );
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\n" ); document.write( "\n" ); document.write( "Description seems imprecise. Most of it does not force any change. Expecting that the actual price for camera is not p,
\n" ); document.write( "but is to be 1.25p. Description clearly said, Amy pay 30% of the usual price. Effect of this from actual price not important.\r
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\n" ); document.write( "\n" ); document.write( "(a) What is the usual price of the camera?
\n" ); document.write( "\"0.3p=255\"\r
\n" ); document.write( "\n" ); document.write( "\"p=255%2F0.3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p=850%29\"
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