document.write( "Question 1200910: A club with 20 women and 17 men needs to form a committee of size six.
\n" ); document.write( "How many committees are possible?
\n" ); document.write( "How many committees are possible if the committee must have three women and three men?
\n" ); document.write( "How many committees are possible if the committee must have at least two men?
\n" ); document.write( "How many committees are possible if the committee must consist of all women or all men?
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Algebra.Com's Answer #835142 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Question 1
\n" ); document.write( "A club with 20 women and 17 men needs to form a committee of size six.
\n" ); document.write( "How many committees are possible?
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\n" ); document.write( "\n" ); document.write( "The seats on the committee aren't named and have equal rank.
\n" ); document.write( "This means the order doesn't matter.
\n" ); document.write( "We use the nCr combination formula.\r
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\n" ); document.write( "\n" ); document.write( "n = 20 women + 17 men = 37 people total
\n" ); document.write( "r = 6 selections
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "37 C 6 = (37!)/(6!*(37-6)!)
\n" ); document.write( "37 C 6 = (37!)/(6!*31!)
\n" ); document.write( "37 C 6 = (37*36*35*34*33*32*31!)/(6!*31!)
\n" ); document.write( "37 C 6 = (37*36*35*34*33*32)/(6!)
\n" ); document.write( "37 C 6 = (37*36*35*34*33*32)/(6*5*4*3*2*1)
\n" ); document.write( "37 C 6 = (1673844480)/(720)
\n" ); document.write( "37 C 6 = 2324784\r
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\n" ); document.write( "\n" ); document.write( "Answer: 2,324,784
\n" ); document.write( "This is roughly 2.3 million\r
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\n" ); document.write( "Question 2
\n" ); document.write( "A club with 20 women and 17 men needs to form a committee of size six.
\n" ); document.write( "How many committees are possible if the committee must have three women and three men?
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\r
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\n" ); document.write( "\n" ); document.write( "There are n = 20 women and there are r = 3 selections.
\n" ); document.write( "Use the nCr combination formula.
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "20 C 3 = (20!)/(3!*(20-3)!)
\n" ); document.write( "20 C 3 = (20!)/(3!*17!)
\n" ); document.write( "20 C 3 = (20*19*18*17!)/(3!*17!)
\n" ); document.write( "20 C 3 = (20*19*18)/(3!)
\n" ); document.write( "20 C 3 = (20*19*18)/(3*2*1)
\n" ); document.write( "20 C 3 = (6840)/(6)
\n" ); document.write( "20 C 3 = 1140
\n" ); document.write( "Take note of the 20*19*18 in the numerator and 3! = 3*2*1 = 6 in the denominator.
\n" ); document.write( "There are 1140 ways to pick the three women where order doesn't matter.\r
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\n" ); document.write( "\n" ); document.write( "Follow similar steps for the men.
\n" ); document.write( "n = 17
\n" ); document.write( "r = 3
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "17 C 3 = (17!)/(3!*(17-3)!)
\n" ); document.write( "17 C 3 = (17!)/(3!*14!)
\n" ); document.write( "17 C 3 = (17*16*15*14!)/(3!*14!)
\n" ); document.write( "17 C 3 = (17*16*15)/(3!)
\n" ); document.write( "17 C 3 = (17*16*15)/(3*2*1)
\n" ); document.write( "17 C 3 = (4080)/(6)
\n" ); document.write( "17 C 3 = 680
\n" ); document.write( "There are 680 ways to pick the three men where order doesn't matter.\r
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\n" ); document.write( "\n" ); document.write( "Summary:
\n" ); document.write( "1140 ways to pick the three women
\n" ); document.write( "680 ways to pick the three men\r
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\n" ); document.write( "\n" ); document.write( "Therefore, 1140*680 = 775,200 is the number of ways to have a committee of 3 women and 3 men. Order doesn't matter.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 775,200\r
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\n" ); document.write( "Question 3
\n" ); document.write( "A club with 20 women and 17 men needs to form a committee of size six.
\n" ); document.write( "How many committees are possible if the committee must have at least two men?
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\n" ); document.write( "\n" ); document.write( "Let's consider the event \"at most 1 man\".
\n" ); document.write( "It can be broken down into these two cases:
\n" ); document.write( "Case A: 6 women and 0 men on the committee
\n" ); document.write( "Case B: 5 women and 1 man on the committee\r
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\n" ); document.write( "\n" ); document.write( "Case A:
\n" ); document.write( "20C6 = 38,760 ways to pick the women
\n" ); document.write( "17C0 = 1 way to pick the men (i.e. 1 way to leave the men out entirely)
\n" ); document.write( "38,760*1 = 38,760 different ways to do case A.\r
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\n" ); document.write( "\n" ); document.write( "Case B:
\n" ); document.write( "20C5 = 15,504 ways to pick the women
\n" ); document.write( "17C1 = 17 ways to pick the men
\n" ); document.write( "15,504*17 = 263,568 different ways to do case B.\r
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\n" ); document.write( "\n" ); document.write( "We have
\n" ); document.write( "A+B = 38,760+263,568 = 302,328
\n" ); document.write( "ways to have at most 1 man.\r
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\n" ); document.write( "\n" ); document.write( "This is out of 37C6 = 2,324,784 ways to form the committee (refer to question 1).\r
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\n" ); document.write( "\n" ); document.write( "2,324,784 - 302,328 = 2,022,456
\n" ); document.write( "This is the number of ways to have at least two men. \r
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\n" ); document.write( "\n" ); document.write( "The events \"at most 1 man\" and \"at least two men\" are complementary.
\n" ); document.write( "They make up all possible outcomes.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 2,022,456\r
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\n" ); document.write( "Question 4
\n" ); document.write( "A club with 20 women and 17 men needs to form a committee of size six.
\n" ); document.write( "How many committees are possible if the committee must consist of all women or all men?
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\r
\n" ); document.write( "\n" ); document.write( "Let's determine how many committees are possible if the committee consists of women only.
\n" ); document.write( "n = 20 women
\n" ); document.write( "r = 6 selections
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "20 C 6 = (20!)/(6!*(20-6)!)
\n" ); document.write( "20 C 6 = (20!)/(6!*14!)
\n" ); document.write( "20 C 6 = (20*19*18*17*16*15*14!)/(6!*14!)
\n" ); document.write( "20 C 6 = (20*19*18*17*16*15)/(6!)
\n" ); document.write( "20 C 6 = (20*19*18*17*16*15)/(6*5*4*3*2*1)
\n" ); document.write( "20 C 6 = (27907200)/(720)
\n" ); document.write( "20 C 6 = 38760\r
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\n" ); document.write( "\n" ); document.write( "Now let's see how many committees are possible if the committee consists of men only.
\n" ); document.write( "n = 17 men
\n" ); document.write( "r = 6 selections
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "17 C 6 = (17!)/(6!*(17-6)!)
\n" ); document.write( "17 C 6 = (17!)/(6!*11!)
\n" ); document.write( "17 C 6 = (17*16*15*14*13*12*11!)/(6!*11!)
\n" ); document.write( "17 C 6 = (17*16*15*14*13*12)/(6!)
\n" ); document.write( "17 C 6 = (17*16*15*14*13*12)/(6*5*4*3*2*1)
\n" ); document.write( "17 C 6 = (8910720)/(720)
\n" ); document.write( "17 C 6 = 12376\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "38,760 ways to have a committee of all women.
\n" ); document.write( "12,376 ways to have a committee of all men.
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