document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200907>Question 1200907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the vertex angle of an isosceles triangle is 10 degrees less than thrice the measure of one of its base angles. Find the measure of the vertex angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835138 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let B equal one of the base angles.<BR>\n" );
document.write( "let V equal the vertex angle.<BR>\n" );
document.write( "you get:<BR>\n" );
document.write( "180 = 2A + V<BR>\n" );
document.write( "V = 3A - 10<BR>\n" );
document.write( "replace V in the firsts equation with 3A - 10 from the second equation to get:<BR>\n" );
document.write( "180 = 2A + 3A - 10<BR>\n" );
document.write( "add 10 to both sides of the equation and combine like terms to get:<BR>\n" );
document.write( "190 = 5A<BR>\n" );
document.write( "solve for A to get:<BR>\n" );
document.write( "A = 190/5 = 38<BR>\n" );
document.write( "V = 3A - 10 = 3*38 - 10 = 114 - 10 = 104<BR>\n" );
document.write( "confirm by:<BR>\n" );
document.write( "180 = 2 * 38 + 104 = 76 + 104 = 180<BR>\n" );
document.write( "your solution is that the vertex angle is 104 degrees.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );