document.write( "Question 1200867: James invested Php20,000 for one year and earned Php1470 interest. if part of the money is invested at 10%and the remainder is invested at 6%, how much is invested at each rate?\r
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Algebra.Com's Answer #835091 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "James invested Php20,000 for one year and earned Php1470 interest.
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document.write( "x         dollars invested at 10%,\r\n" );
document.write( "(20000-x) dollars invested at  6%.\r\n" );
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document.write( "The total annual interest equation is\r\n" );
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document.write( "    0.1x + 0.06(20000-x) = 1470  dollars.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    0.04x + 1200 = 1470\r\n" );
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document.write( "    0.04x = 1470 - 1200\r\n" );
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document.write( "    0.04x = 270\r\n" );
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document.write( "        x = 270/0.04 = 6750.\r\n" );
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document.write( "ANSWER.  $6750 invested at 10%;  the rest 20000 - 6750 = 13250 dollars invested at 6%.\r\n" );
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document.write( "CHECK.   0.1*6750 + 0.06*13250 = 1470 dollars, total annual interest.  ! correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems using one equation in one unknown,  look into the lesson\r
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems using systems of two equations in two unknowns,  look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Using systems of equations to solve problems on investment\r
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