document.write( "Question 1200841: I am a three-digit number. my digits are 3, 5, and 7. I am divisible by 3, 5, and 7. What number am I? \n" ); document.write( "
Algebra.Com's Answer #835064 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 735\r
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\n" ); document.write( "\n" ); document.write( "Reason:
\n" ); document.write( "35 is a multiple of 7 (since 7*5 = 35)
\n" ); document.write( "The same goes for 735 (because 700+35 = 735; both 700 and 35 are multiples of 7).\r
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\n" ); document.write( "\n" ); document.write( "735 is a multiple of 5 because it ends in 5.\r
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\n" ); document.write( "\n" ); document.write( "735 is a multiple of 3 because the digits add to 7+3+5 = 15 which is a multiple of 3.\r
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\n" ); document.write( "\n" ); document.write( "The prime factorization is
\n" ); document.write( "735 = 3*5*7^2
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