document.write( "Question 1200844: To qualify for special training, athletes are tested for endurance.
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document.write( "The scores are normally distributed with a mean of 840 and a standard
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document.write( "deviation of 89. If only the top 15% of the athletes are selected, what would
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document.write( "the cutoff score be? \n" );
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Algebra.Com's Answer #835053 by Theo(13342)![]() ![]() You can put this solution on YOUR website! top 15% would be those with scores above 932.243. \n" ); document.write( "calculator i used can be found at https://davidmlane.com/hyperstat/z_table.html \n" ); document.write( "here's a display of the results. \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you use z-cores, you would do the followng. \n" ); document.write( "the z-score with 15% of the area under the normnal distribution cure to the right of it is equal to 1.03643338. \n" ); document.write( "z-score formuls is z = (x - m) / s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation \n" ); document.write( "formula becomes 1.03643338 = (x - 840) / 89. \n" ); document.write( "solve for x to get x = 89 * 1.03643338 + 840 = 923.2425708. \n" ); document.write( "round to 923.243 as shown in the calculator. \n" ); document.write( " |