document.write( "Question 1200805: The height h metres of a ball at time t second after it is thrown up into the air Is given by the expression
\n" ); document.write( "h= 1+ 15t - 5t^2
\n" ); document.write( "(i) Find the times at which the height is 11m
\n" ); document.write( "(ii) Use your calculator to find the time when the ball hits the ground
\n" ); document.write( "(iii) what is the greatest height the ball reaches
\n" ); document.write( "

Algebra.Com's Answer #835016 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The height h metres of a ball at time t second after it is thrown up into the air Is given by the expression
\n" ); document.write( "h= 1+ 15t - 5t^2
\n" ); document.write( "(i) Find the times at which the height is 11m
\n" ); document.write( "h= 1+ 15t - 5t^2 = 11
\n" ); document.write( "5t^2 - 15t + 10 = 0
\n" ); document.write( "t^2 - 3t + 2 = 0
\n" ); document.write( "(t-1)*(t-2) = 0
\n" ); document.write( "t = 1, t = 2 seconds.
\n" ); document.write( "------------------------
\n" ); document.write( "(ii) Use your calculator to find the time when the ball hits the ground
\n" ); document.write( "h= 1+ 15t - 5t^2 = 0\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-5x%5E2%2B15x%2B1+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2815%29%5E2-4%2A-5%2A1=245\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=245 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-15%2B-sqrt%28+245+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%2815%29%2Bsqrt%28+245+%29%29%2F2%5C-5+=+-0.0652475842498529\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2815%29-sqrt%28+245+%29%29%2F2%5C-5+=+3.06524758424985\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"-5x%5E2%2B15x%2B1\" can be factored:
\n" ); document.write( " \"-5x%5E2%2B15x%2B1+=+%28x--0.0652475842498529%29%2A%28x-3.06524758424985%29\"
\n" ); document.write( " Again, the answer is: -0.0652475842498529, 3.06524758424985.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-5%2Ax%5E2%2B15%2Ax%2B1+%29\"

\n" ); document.write( "\n" ); document.write( "Ignore the negative value.
\n" ); document.write( "----------------
\n" ); document.write( "(iii) what is the greatest height the ball reaches
\n" ); document.write( "The vertex of the parabola is at t = -b/2a
\n" ); document.write( "t = -15/-10 = 1.5 seconds
\n" ); document.write( "h(1.5) = 12.25 meters
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