document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200801>Question 1200801</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the motion of a particle from 0 is describe by the equation 6S = 2t³ - 15t² + 12t, where S is the distance in mitre and t in time in second. fine the acceleration of the particle when it is momentarily at rest </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #835014 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=835014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S(t) = 1/6*(2t³ - 15t² + 12t)<BR>\n" );
document.write( "The velocity of the particle is given by dS/dt:<BR>\n" );
document.write( "v(t) = t² - 5t + 2<BR>\n" );
document.write( "And the acceleration is given by dv/dt:<BR>\n" );
document.write( "a(t) = 2t - 5<BR>\n" );
document.write( "The particle is at rest when v(t) = 0<BR>\n" );
document.write( "0 = t² - 5t + 2 which has solutions t = 0.438447 and 4.561550 s.<BR>\n" );
document.write( "So the acceleration is a(0.438447) = -4.123 and a(4.56155) = 4.123 m/s^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );