document.write( "Question 1200739: If the Fathers age is 5 times his son's age. 4 years back the father was 9 times older than son. what is the fathers present age.? \n" ); document.write( "
Algebra.Com's Answer #834944 by Theo(13342)\"\" \"About 
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f = father's age
\n" ); document.write( "x = his son's age.
\n" ); document.write( "f = 5x
\n" ); document.write( "f-4 = 9*(x-4)
\n" ); document.write( "in the second equation replace f with 5x to get:
\n" ); document.write( "5x-4 = 9*(x-4)
\n" ); document.write( "simplify to get:
\n" ); document.write( "5x-4 = 9x-36
\n" ); document.write( "subtract 5x from both sides of the equation and add 36 to both sides of the equation to get:
\n" ); document.write( "32 = 4x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 8
\n" ); document.write( "f = 5x means f = 40
\n" ); document.write( "f-4 = 36
\n" ); document.write( "x-4 = 4
\n" ); document.write( "36 = 9 * 4.
\n" ); document.write( "solution is confirmed to be good.
\n" ); document.write( "solution is father's present age is 40.
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