document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200705>Question 1200705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a classroom of 24 students, the teacher forms groups of 6 students each. How many different ways can these groups be formed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #834917 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=834917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Interpret the problem differently than the other tutor; it seems to me all 24 students must be formed into groups of 6.<br><BR>\n" );
document.write( "To form the first group, the teacher can choose any 6 of the 24 students; the number of ways to do that is \"24 choose 6\", C(24,6).<br><BR>\n" );
document.write( "Then there are 18 students left with which to form the second group of 6 -- in C(18,6) ways.<br><BR>\n" );
document.write( "And then C(12,6) ways to form the third group, and finally C(6,6) ways to form the last.  Of course C(6,6) is 1, because with 6 students left there is only one way to form a group of 6.<br><BR>\n" );
document.write( "ANSWER: C(24,6)*C(18,6)*C(12,6)*C(6,6) = ...(large number....)<br><BR>\n" );
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