document.write( "Question 1200408: Many people believe that the average number of Facebook friends is 338. The population standard deviation is 43.2. A random sample of 50 high school students in a particular district revealed that the average number of Facebook friends was 350. At alpha=0.05, is there sufficient evidence to conclude that the mean number of friends is greater than 338? \n" ); document.write( "
Algebra.Com's Answer #834829 by Theo(13342)\"\" \"About 
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population average is assumed to be 338.
\n" ); document.write( "population standard deviation is 43.2
\n" ); document.write( "sample of 50 students reveals that the average number of facebook friends is 350.
\n" ); document.write( "test is to see if the average is greater than 338.
\n" ); document.write( "one tailed alpha is indicated on the high end because the text is for greater than.
\n" ); document.write( "at .05 alpha, on the high end, the critical z-score will be 1.644853626.
\n" ); document.write( "z-score formula is z = (x-m)/s
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the sample mean
\n" ); document.write( "m is the assumed population mean
\n" ); document.write( "s is the standard error.
\n" ); document.write( "standard error = standard deviation divided by square root of sample size = 43.2 / sqrt(50) = 6.209402589.
\n" ); document.write( "test z-score = (350 - 338) / 6.209402589 = 1.964185503.
\n" ); document.write( "since this is greater than the critical z-score, the test results are significant and the conclusion is that the verage is most probably greater than 338.
\n" ); document.write( "you could also test with alpha.
\n" ); document.write( "the results will be consistent with the critical z-score test.
\n" ); document.write( "the critical alpha is .05 on the high end.
\n" ); document.write( "the area to the right of the test z-score is .0247542216.
\n" ); document.write( "since this is less than the critical alpha, the results are, once again, considered significant, leading to the same conclusion.\r
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