document.write( "Question 114470: The half-life of silicon-32 is 710 years. If 10 grams are presents now, how much will be present in 600 years? \n" ); document.write( "
Algebra.Com's Answer #83482 by ankor@dixie-net.com(22740)\"\" \"About 
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The half-life of silicon-32 is 710 years. If 10 grams are presents now, how much will be present in 600 years?
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\n" ); document.write( "The half-life equation:
\n" ); document.write( "A = Ao(2^(-t/h))
\n" ); document.write( "Where:
\n" ); document.write( "A = resulting amt after t years
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "t = time
\n" ); document.write( "h = half-life of the substance
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\n" ); document.write( "In your problem, find A when:
\n" ); document.write( "Ao = 10 grams
\n" ); document.write( "t = 600 years
\n" ); document.write( "h = 710 yrs is the half life of silicon-32
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\n" ); document.write( "A = 10(2^(-600/710))
\n" ); document.write( "A = 10*.55668; find 2^(-60/71) on a good calculator
\n" ); document.write( "A = 5.5668 grams after 600 yrs
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\n" ); document.write( "That's not so hard, is it? \n" ); document.write( "
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