document.write( "Question 1200644: a theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first. The tax in the first city was 10%, and the tax in the second city was 6%. The total hotel tax paid for the two cities was $
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Algebra.Com's Answer #834818 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "a theater group made appearances in two cities.
\n" ); document.write( "The hotel charge before tax in the second city was $1000 lower than in the first.
\n" ); document.write( "The tax in the first city was 10%, and the tax in the second city was 6%.
\n" ); document.write( "The total hotel tax paid for the two cities was $420.
\n" ); document.write( "How much was the hotel charge in each city before tax?
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document.write( "Let x be the hotel charge in the first city before tax, in dollars.\r\n" );
document.write( "Then that in the second city is (x-1000) dollars.\r\n" );
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document.write( "Write the total hotel tax paid for the two cities\r\n" );
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document.write( "    0.1x + 0.06(x-1000) = 420  dollars.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    0.1x + 0.06x - 60 = 420\r\n" );
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document.write( "        0.16x         = 420 + 60 = 480\r\n" );
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document.write( "            x                    = 480/0.16 = 3000.\r\n" );
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document.write( "ANSWER.  $3000 in the first city and $2000 in the second city.\r\n" );
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document.write( "CHECK.  0.1*3000 + 0.06*2000 = 300 + 120 = 420  dollars.   ! correct !\r\n" );
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