document.write( "Question 1200289: A ship is heading in a direction N 60◦E at a speed which in still water would be 20 km/h. It is carried off course by a current of 8 km/h in a direction of E50s. Calculate the ship’s actual speed and direction. \n" ); document.write( "
Algebra.Com's Answer #834791 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A ship is heading in a direction N 60◦E at a speed which in still water would be 20 km/h. It is carried off course by a current of 8 km/h in a direction of E50s. Calculate the ship’s actual speed and direction.
\n" ); document.write( "------------
\n" ); document.write( "Draw a vector OA with its tail at the Origin.
\n" ); document.write( "The heading of the boat, vector OA, is 060 degs.
\n" ); document.write( "The wind direction is 140 degs.
\n" ); document.write( "Draw a vector AB with the tail at A.
\n" ); document.write( "The angle OAB is 100 degrees.
\n" ); document.write( "----
\n" ); document.write( "Use the Cosine Law to find the resultant OB.
\n" ); document.write( "r^2 = 20^2 + 8^2 - 2*8*20*cos(100)
\n" ); document.write( "r^2 = ~ 519.57
\n" ); document.write( "r = ~22.79 km/hr
\n" ); document.write( "--------------------
\n" ); document.write( "Use the Sine Law to find angle AOB:
\n" ); document.write( "r/sin(100) = 8/sin(AOB)
\n" ); document.write( "sin(AOB) = 8*sin(100)/20 = ~0.3939
\n" ); document.write( "AOB = ~23.2 degs
\n" ); document.write( "bearing = 60 + AOB = 83.2 degs \n" ); document.write( "
\n" );