document.write( "Question 1200581: A company has a 20-person grievance committee. When a grievance is filed, three of these
\n" ); document.write( "20 people are chosen at random to serve on a hearing panel. Suppose that two committees are
\n" ); document.write( "formed. What is the probability that these committees have at least one member in common?
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Algebra.Com's Answer #834741 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The probability that the first person chosen for the second panel is not on the first panel is 17/20.
\n" ); document.write( "The probability that the second person chosen for the second panel is not on the first panel is 16/19.
\n" ); document.write( "The probability that the third person chosen for the second panel is not on the first panel is 15/18.

\n" ); document.write( "So the probability that none of the three people chosen for the second panel are on the first panel is (17/20)(16/19)(15/18) = 0.5965 (rounded).

\n" ); document.write( "Then the probability that at least one member of the second panel is on the first panel is 1-0.5965 = 0.4035.

\n" ); document.write( "ANSWER: 0.4035
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