document.write( "Question 1200567: A collection of nickels, dimes, and quarters is retrieved from a vending machine. There are three times as many nickels as dimes, and there are ten more quarters than dimes. If the total value of the coins is $40.00 then find the number of each type of coin.
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Algebra.Com's Answer #834718 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "A collection of nickels, dimes, and quarters is retrieved from a vending machine.
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\n" ); document.write( "\n" ); document.write( "            It may seem fantastic,  but the problem can be \r
\n" ); document.write( "\n" ); document.write( "            solved mentally,  without using equations.\r
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document.write( "Take 10 quarters aside, for a minute.\r\n" );
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document.write( "Then the updated collection has three times as many nickels as dimes, \r\n" );
document.write( "and the same number of quarters as dimes and it is worth \r\n" );
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document.write( "    40.00 - 10*0.25 = 40 - 2.50 = 37.50 dollars.\r\n" );
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document.write( "Now group the coins in the sets, combining 1 dime, three nickels and 1 quarter in each set.\r\n" );
document.write( "According to the problem, it CAN BE DONE.\r\n" );
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document.write( "Each set is worth  10 + 3*5 + 25 = 50 cents; so, the number of sets is  \"37.50%2F0.5\" = 75.\r\n" );
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document.write( "From this, we conclude that the original collection has \r\n" );
document.write( "75 dimes, 3*75 = 225 nickels and 75+10 = 85 quarters.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Good problem for a school  Math circle to give it to advanced students
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\n" ); document.write( "\n" ); document.write( "If a Math teacher wants to bring up students with vivid mind, he (or she)
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