document.write( "Question 1200567: A collection of nickels, dimes, and quarters is retrieved from a vending machine. There are three times as many nickels as dimes, and there are ten more quarters than dimes. If the total value of the coins is $40.00 then find the number of each type of coin.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #834716 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "225 nickels \n" ); document.write( "75 dimes \n" ); document.write( "85 quarters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = number of dimes \n" ); document.write( "3d = number of nickels \n" ); document.write( "d+10 = number of quarters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10d = value of the dimes (cents) \n" ); document.write( "5(3d) = 15d = value of the nickels (cents) \n" ); document.write( "25(d+10) = 25d+250 = value of the quarters (cents)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10d+15d+(25d+250) = 4000 cents aka $40 \n" ); document.write( "50d+250 = 4000 \n" ); document.write( "50d = 4000-250 \n" ); document.write( "50d = 3750 \n" ); document.write( "d = 3750/50 \n" ); document.write( "d = 75 dimes \n" ); document.write( "3d = 3*75 = 225 nickels \n" ); document.write( "d+10 = 75+10 = 85 quarters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "225 nickels = 225*5 = 1125 cents = $11.25 \n" ); document.write( "75 dimes = 75*10 = 750 cents = $7.50 \n" ); document.write( "85 quarters = 85*25 = 2125 cents = $21.25 \n" ); document.write( "total = $11.25+$7.50+$21.25 = $40 \n" ); document.write( "The answers are confirmed. \n" ); document.write( " \n" ); document.write( " |