document.write( "Question 113876: Fifteen years from now Darren will be four times as old as he was three years ago. How old is Darren now? \n" ); document.write( "

Algebra.Com's Answer #83471 by BurningFlame_marc(77) $\"\"$ $\"About$

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Hello!\r
\n" ); document.write( "\n" ); document.write( "I will show you how I solve these kinds of problems.\r
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\n" ); document.write( "\n" ); document.write( "Representation:
\n" ); document.write( "Let x-3 be the age of darren 3 years ago, x+15 be his age 15 years from now.\r
\n" ); document.write( "\n" ); document.write( "Equation:
\n" ); document.write( "x+15=4(x-3)\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "x+15=4(x-3)
\n" ); document.write( "x=4x-12-15
\n" ); document.write( "x=4x-27
\n" ); document.write( "-3x=-27
\n" ); document.write( "3x=27
\n" ); document.write( "x=9\r
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\n" ); document.write( "\n" ); document.write( "Final Answer:
\n" ); document.write( "He is now 9 years old... \n" ); document.write( "

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