document.write( "Question 114659: I have tried everything and I just don't understand this problem.
\n" ); document.write( "Here is the problem \r
\n" ); document.write( "\n" ); document.write( "\"log%286%2C36%29\" = \"5x+%2B+3\"\r
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Algebra.Com's Answer #83466 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
I have tried everything and I just don't understand this problem.
\n" ); document.write( "Here is the problem \r
\n" ); document.write( "\n" ); document.write( "\"+log%286%2C36%29+\" = \"5x+%2B+3\"\r
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\n" ); document.write( "\n" ); document.write( "We use the definition of a logarithm:\r
\n" ); document.write( "\n" ); document.write( "which says this: \r
\n" ); document.write( "\n" ); document.write( "The equation logA = C \r
\n" ); document.write( "\n" ); document.write( "is equivalent to this equation\r
\n" ); document.write( "\n" ); document.write( "BC = A\r
\n" ); document.write( "\n" ); document.write( "That means that your equation:\r
\n" ); document.write( "\n" ); document.write( "\"log%286%2C36%29\" = \"5x+%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "is equivalent to and can be replaced by
\n" ); document.write( "the equation:\r
\n" ); document.write( "\n" ); document.write( "\"6%5E%285x%2B3%29\" = \"36\"\r
\n" ); document.write( "\n" ); document.write( "Now since 6×6=36, we can write 36 as 62\r
\n" ); document.write( "\n" ); document.write( "\"6%5E%285x%2B3%29\" = \"6%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Now since the base 6 is positive and not equal to 1,
\n" ); document.write( "we can equate the exponents of 6 on both sides:\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B3\" = \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"5x\" = \"2-3\"\r
\n" ); document.write( "\n" ); document.write( "\"5x\" = \"-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x\" = \"-1%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Edwin
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