document.write( "Question 1200511: How much 50% antifreeze solution and 40% antifreeze solution should be combined to give 50 gallons of 46% antifreeze solution?
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Algebra.Com's Answer #834659 by josgarithmetic(39618) $\"\"$ $\"About$

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h of the 50%
\n" ); document.write( "50-h of the 40%
\n" ); document.write( "Result Wanted, 50 gallons of 46%\r
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\n" ); document.write( "\n" ); document.write( " $\"50h%2B40%2850-h%29=46%2A50\"$ , to account for amount of pure antifreeze.\r
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\n" ); document.write( "\n" ); document.write( " $\"50h-40h%2B40%2A50=46%2A50\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%2850-40%29h=46%2A50-40%2A50\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"h%2850-40%29=50%2846-40%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight_green%28h=50%28%2846-40%29%2F%2850-40%29%29%29\"$ ---------The computations were not yet done, so you can think about the form of this expression for variable h. ....
\n" ); document.write( "Now, compute h, and use it to evaluate 50-h. \n" ); document.write( "

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