document.write( "Question 1200490: The range of a projectile is the horizontal distance it travels before it reaches the ground. The greatest range is achieved if the projectile is thrown at 45° to the horizontal.
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Algebra.Com's Answer #834638 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The range of a projectile is the horizontal distance it travels before it reaches the ground.
\n" ); document.write( "The greatest range is achieved if the projectile is thrown at 45° to the horizontal.
\n" ); document.write( "A ball is thrown with an initial velocity of 40 ms^-1, Calculate its greatest possible range
\n" ); document.write( "when air resistance is considered to be negligible.
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document.write( "So, the angle to the horizon of the initial velocity is assumed to be 45°.\r\n" );
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document.write( "At this condition, the horizontal component of the velocity is \r\n" );
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document.write( "     = 40*cos(45°) = 40*(sqrt(2)/2) = 40*0.707 = 28.285 m/s;\r\n" );
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document.write( "The vertical component of the velocity is\r\n" );
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document.write( "     = 40*sin(45°) = 40*(sqrt(2)/2) = 40*0.707 = 28.285 m/s  \r\n" );
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document.write( "(has the same numerical value as the horizontal component).\r\n" );
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document.write( "The flight time is  t =  =  = 5.767 seconds (approximately).\r\n" );
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document.write( "    Here g = 9.81 m/s^2  is the gravity acceleration at the Earth surface.\r\n" );
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document.write( "The horizontal distance to fly (the range) is   = 28.285*5.767 = 163.120 m (rounded).\r\n" );
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document.write( "ANSWER.  The greatest possible range is approximately 163.120 m under given conditions.\r\n" );
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