document.write( "Question 1200493: A private airplane leaves an airport and flies due east at 192 km/hr. Two hours later, a jet leaves the same airport and flies due east at 960 km/hr. How long after the jet leaves will it overtake the plane?
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Algebra.Com's Answer #834637 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "kph = kilometers per hour\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's call the planes A and B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plane A travels east at 192 kph \n" ); document.write( "Plane B travels east at 960 kph, taking off 2 hours later.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = slower plane \n" ); document.write( "B = faster plane\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = amount of time the faster plane is in the air.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The slower plane got a 2 hour head start, so x+2 represents the number of hours the slower plane is flying.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plane A \n" ); document.write( "distance = rate*time \n" ); document.write( "distance = 192*(x+2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plane B \n" ); document.write( "distance = rate*time \n" ); document.write( "distance = 960*x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The faster plane passes the slower one when the two aircraft have traveled the same distance. \n" ); document.write( "distanceA = distanceB \n" ); document.write( "192*(x+2) = 960x \n" ); document.write( "192x+384 = 960x \n" ); document.write( "384 = 960x-192x \n" ); document.write( "384 = 768x \n" ); document.write( "x = 384/768 \n" ); document.write( "x = 0.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This leads to x+2 = 0.5+2 = 2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plane A is in the air for 2.5 hrs (aka 2.5*60 = 150 min, aka 2 hrs + 30 min) \n" ); document.write( "Plane B is in the air for 0.5 hrs (aka 0.5*60 = 30 min)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "plane A's distance = 192*2.5 = 480 km \n" ); document.write( "plane B's distance = 960*0.5 = 480 km \n" ); document.write( "Both have traveled the same distance, so the answer is confirmed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.5 hours aka 30 minutes \n" ); document.write( " \n" ); document.write( " |