document.write( "Question 1200469: A car travels from town P for 50km due
\n" ); document.write( "North to town Q. It then travels 80km on
\n" ); document.write( "bearing of 270° to town R. Find: (a) The
\n" ); document.write( "shortest distance from town P to town R
\n" ); document.write( "(b) The bearing of town R from P (c) bearing
\n" ); document.write( "of P from R.
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Algebra.Com's Answer #834608 by Alan3354(69443)\"\" \"About 
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A car travels from town P for 50km due
\n" ); document.write( "North to town Q. It then travels 80km on
\n" ); document.write( "bearing of 270° to town R. Find: (a) The
\n" ); document.write( "shortest distance from town P to town R
\n" ); document.write( "(b) The bearing of town R from P (c) bearing
\n" ); document.write( "of P from R.
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\n" ); document.write( "a) It's a right triangle with sides of 50 and 80
\n" ); document.write( "d^2 - 50^2 + 80^2 = 8900
\n" ); document.write( "d = ~94.34 km
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\n" ); document.write( " b) & c)
\n" ); document.write( "tan(P) = 80/50
\n" ); document.write( "P = 58 degs
\n" ); document.write( "Bearing form P to R = 302 degs
\n" ); document.write( "Bearing from R to P = 360 - 302 = 058 degs
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